shortguy on indom

OUT OF CURIOSITY, WHAT COMMON METRIC(S) IS CURRENTLY BEING USED? "As long as the enemy groups do not have too much variance, and similar characters are used each run, the test results should show usable deltas." AGREE WITH THAT STATEMENT WHOLEHEARTEDLY, FROM A DIFF THREAD.

AGREE... WoC ON A DARK MAP CAN GET A BIT JIGGY. "MY EYES!"

GOLDEN MEAN FALLACY. ...CANNOT ELABORATE FOR OBVIOUS REASONS.

HOMOGENATION FOR PLAYERS = NO HOMOGENATION OF ENEMIES = YES, PROBABLY.

YES, EVERYONE UNDERSTANDS THE RULES WITHOUT THEM NEEDING TO BE SPELLED OUT. 50%

CONSPIRACY THEORY? BEEN AWHILE, SEEMS LEGIT?

THIS THREAD SHOULD BE MOVED TO THE "SUGGESTIONS" SUB-FORUM, WHERE THE REVIEWER WILL REGRET THAT THEY POSTED ANYTHING AT ALL.

cannot spin outta this one eh? ... can youuuuu dig it!

more... from copilot: believe this would be if enemy threw a splat attack: (of course this is if enemy had 50% final chance to hit...but you get the idea). may you please solve the all 8 events dependent on one another as above if each event has 50% probability? Certainly! Since each event has a probability of 50% (or 0.5) and all 8 events are dependent on one another, the overall probability of all 8 occurring follows this formula: P(A1)×P(A2∣A1)×P(A3∣A1,A2)×⋯×P(A8∣A1,A2,...,A7)P(A_1) \times P(A_2 | A_1) \times P(A_3 | A_1, A_2) \times \dots \times P(A_8 | A_1, A_2, ..., A_7) Since each event has a conditional probability of 50%, the calculation becomes: 0.5×0.5×0.5×0.5×0.5×0.5×0.5×0.5=0.580.5 \times 0.5 \times 0.5 \times 0.5 \times 0.5 \times 0.5 \times 0.5 \times 0.5 = 0.5^8 =0.0039 or 0.39%

not me, copilot answer here. lol. chance of all 8 events happening The chance of all 8 events happening depends on the probability of each individual event and whether they are independent or dependent on one another. If all 8 events are independent and each has its own probability, you multiply their probabilities together to get the likelihood of all occurring. For example, if each event has a probability of 50% (0.5), the chance of all 8 happening would be: 0.58=0.0039 or 0.39%0.5^8 = 0.0039 \text{ or } 0.39\% If some of these events are dependent, their probabilities might change based on previous outcomes. If you have specific probabilities for each event, I can help you calculate the overall probability more precisely!

disingenuous... good lawyer and true, but it has everything to do with reality.

in a team setting... sure. a mix of 10%/35% or any other combo of def to tohitdebuff that sums to 45%. can you dig it?

another reality... if playing on a full team there is only a 1 of 8 chance of being hit by a range attack, right?

all hype, disingenuous at least. one could have 0% defense and 45% tohitdebuff and it would yield same result according to the formula.